Question

Write an equation in slope-intercept form of the line that passes through the given point and is

perpendicular to the graph of the given equation.
(5,0); y+1=2(x-3)

Answer 1

`y=(-1)/(2)x +(5)/(2)`

Explanation:

Slope intercept form looks like y=mx+b

The slope (m) needs to be the opposite reciprocal of 2, because the line needs to be perpendicular the given line. Therefore, m = -1/2

We can write the equation in point-slope form first because we're given a point and now we have the slope. The equation would be
`y-0=(-1)/(2) (x-5)`

Rewriting, we get
`y=(-1)/(2)x +(5)/(2)`