Question

The net ionic equation for formation of an aqueous solution of NiI2 accompanied by evolution of CO2 gas via mixing solid NiCO3 and aqueous hydriodic acid is __________.A) 2NiCO3 (s) + HI (aq) ® 2H2O (l) + CO2 (g) + 2Ni2+ (aq)B) NiCO3 (s) + I- (aq) ® 2H2O (l) + CO2 (g) + Ni2+ (aq) + HI (aq)C) NiCO3 (s) + 2H+ (aq) ® H2O (l) + CO2 (g) + Ni2+ (aq)D) NiCO3 (s) + 2HI (aq) ® 2H2O (l) + CO2 (g) + NiI2 (aq)E) NiCO3 (s) + 2HI (aq) ® H2O (l) + CO2 (g) + Ni2+ (aq) + 2I- (aq)

Answer 1

First you need to write out the original equation.

`NiCO_(3(s))+ HI_(aq) ->NiI_(2(aq))+CO_(2(g))+H_2O_((l))`

It needs to be balanced, though, so after balancing it should look like this:

`NiCO_(3(s))+ 2HI_(aq) ->NiI_(2(aq))+CO_(2(g))+H_2O_((l))`

The ionic equation would look like this. (Only aqueous solutions can be split up).

`NiCO_(3(s))+ 2H^+_(aq)+2I^-_(aq) ->Ni^(2+)_(aq)+2I^-_((aq))+CO_(2(g))+H_2O_((l))`

The net ionic equation only contains the products that are not aqueous. Therefore, the final net ionic equation should be:

`NiCO_(3(s))+ 2H^+_(aq) ->Ni^(2+)_(aq)+CO_(2(g))+H_2O_((l))`

So your answer is C.