Question

Nancy ate a 500 Cal lunch. Neglecting efficiency issues (i.e., assuming 100% conversion of energy to work), to what height could Nancy raise a 50 kg weight with the energy from her lunch? (Remember, gravitational potential energy is given by: PE = m x g x h and the gravitational constant is equal to 9.81 m/s-2)

The world uses approximately 25 billion kg of H2 per year to make ammonia for fertilizer. The energy cost for this process is approximately 30 GJ per metric ton H2 used. What is the average power requirement for this process, assuming that the ammonia production is approximately constant over a year?

Answer 1

`4265.04\ \text{m}`

`2.38* 10^(10)\ \text{W}`

Step-by-step explanation:

PE = Energy of food = 500 cal =
`500*4184=2.092*10^6\ \text{J}`

m = Mass of object = 50 kg

g = Acceleration due to gravity =
`9.81\ \text{m/s}^2`

Potential energy of food is given by

`PE=mgh\\\Rightarrow h=(PE)/(mg)\\\Rightarrow h=(2.092* 10^6)/(50* 9.81)\\\Rightarrow h=4265.04\ \text{m}`

Nancy could raise the weight to a maximum height of
`4265.04\ \text{m}`.

Mass of
`H_2` used per year =
`25* 10^(9)\ \text{kg/year}`

Energy of
`H_2` =
`(30*10^9)/(1000)=30* 10^6\ \text{J/kg}`

Power

`P=25* 10^(9)\ \text{kg/year}* 30* 10^6\ \text{J/kg}\\\Rightarrow P=7.5* 10^(17)\ \text{J/year}\\\Rightarrow P=(7.5* 10^(17))/(365.25* 24* 60* 60)\\\Rightarrow P=2.38* 10^(10)\ \text{W}`

The power requirement is
`2.38* 10^(10)\ \text{W}`.