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Solve the systems of equations by substitution:
y=2x-1
4x+6y=10

User Peterhil
by
7.6k points

2 Answers

3 votes

Answer:

Explanation:

step 1

y=2x-1,4x+6y=10 Equation

step 2

y=2x-1 solve for y

4x+6y=10 substitute

4x+6(2x-1)=10

step 3

16x-6=10

16x-6+6=10+6 add 6

16x=16

16x/16=16/16

x=1

step 4

y=2x-1 substitute

y=(2)(1)-1

y=1

your two answers are

x=1 and y=1

User Adam Cherti
by
8.4k points
3 votes

Answer:

(1, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Algebra I

  • Solving systems of equations using substitution/elimination

Explanation:

Step 1: Define Systems

y = 2x - 1

4x + 6y = 10

Step 2: Solve for x

Substitution

  1. Substitute in y: 4x + 6(2x - 1) = 10
  2. Distribute 6: 4x + 12x - 6 = 10
  3. Combine like terms: 16x - 6 = 10
  4. Add 6 to both sides: 16x = 16
  5. Divide 16 on both sides: x = 1

Step 3: Solve for y

  1. Define equation: y = 2x - 1
  2. Substitute in x: y = 2(1) - 1
  3. Multiply: y = 2 - 1
  4. Subtract: y = 1
User Alexforrence
by
8.2k points

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