Question

Solve the systems of equations by substitution:
y=2x-1
4x+6y=10

Answer 1

Explanation:

step 1

y=2x-1,4x+6y=10 Equation

step 2

y=2x-1 solve for y

4x+6y=10 substitute

4x+6(2x-1)=10

step 3

16x-6=10

16x-6+6=10+6 add 6

16x=16

16x/16=16/16

x=1

step 4

y=2x-1 substitute

y=(2)(1)-1

y=1

your two answers are

x=1 and y=1

Answer 2

(1, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Equality Properties

Algebra I

• Solving systems of equations using substitution/elimination

Explanation:

Step 1: Define Systems

y = 2x - 1

4x + 6y = 10

Step 2: Solve for x

Substitution

1. Substitute in y: 4x + 6(2x - 1) = 10
2. Distribute 6: 4x + 12x - 6 = 10
3. Combine like terms: 16x - 6 = 10
4. Add 6 to both sides: 16x = 16
5. Divide 16 on both sides: x = 1

Step 3: Solve for y

1. Define equation: y = 2x - 1
2. Substitute in x: y = 2(1) - 1
3. Multiply: y = 2 - 1
4. Subtract: y = 1