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Please answer fast!

You push a 10 kg box across the floor. The box is initially at rest. You apply a force on the box for
0.05 seconds. If the velocity of the box is 50 m/s after you push it, what is the net force you applied
to the box? (Hint: remember impulse! F*t = m*v2 - m*v1)

User HongboZhu
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1 Answer

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Answer:

F = ma The force of friction for a 7.5-kg object being pushed horizontally at a constant A 30-kg wooden box is resting on a carpeted surface. If the ... An applied force of 21 N accelerates a 9.0-kg wagon at 2.0 m/s² along the sidewalk. (u=0,034. 5. A sled of mass of 50.0 kg is pulled along a flat, snow-covered ground.

Step-by-step explanation:

User Cristina Alboni
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