Question

A firecracker is launched into the with an initial velocity of 53.5 m/s. What will be the firecracker’s maximum height, in meters?

Equations used in picture below:

Answer 1

146 m.

Step-by-step explanation:

From the question given above, the following data were obtained:

Initial velocity (vᵢ) = 53.5 m/s

Final velocity (vբ) = 0 (at maximum height)

Acceleration due to gravity (g) = –9.8 m/s² (since the firecracker is going again gravity)

Maximum height (h) =?

Thus, we can obtain the maximum height reached by the firecracker by using the following formula:

vբ² = vᵢ² + 2gh

0² = 53.5² + (2 × –9.8 × h)

0 = 2862.25 + (–19.6h)

0 = 2862.25 – 19.6h

Collect like terms

0 – 2862.25 = – 19.6h

– 2862.25 = – 19.6h

Divide both side by – 19.6

h = – 2862.25 / –19.6

h = 146 m

Therefore, the maximum height reached by the firecracker is 146 m