Question

Pls help quickly!!!

Find the coordinates of the vertex of the graph of the function.
y=3x^2-4x+3

Answer 1

Vertex ( 2/3 , 8/3 )

Answer 2

vertex = (
`(2)/(3)`,
`(8)/(3)` )

Explanation:

given the equation of a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the vertex is

x = -
`(b)/(2a)`

y = 3x² - 4x + 3 ← is in standard form

with a = 3 , b = - 4 , then

x = -
`(-4)/(6)` =
`(2)/(3)`

substitute x =
`(2)/(3)` into the equation for corresponding y- coordinate of vertex

y = 3(
`(2)/(3)` )² - 4(
`(2)/(3)` ) + 3

= 3(
`(4)/(9)` ) -
`(8)/(3)` + 3

=
`(4)/(3)` -
`(8)/(3)` +
`(12)/(3)`

=
`(8)/(3)`

vertex = (
`(2)/(3)`,
`(8)/(3)` )