Answer:
a
b
Generally given that the domain arcsine function is between -1 and 1 then the arcsine of 2.22 will not be valid
Generally given that the domain arcsine function is between -1 and 1 then the arcsine of 2.1 will not be valid
Step-by-step explanation:
From the question we are told that
The slit grating is
![N = 68 \ slits / cm = 6800 \ slits / m](https://img.qammunity.org/2021/formulas/physics/college/mljq05yow1lzf2s8m22jz3dxr2l86sj9v6.png)
The order of spectrum is
Generally the width of the slit is mathematically represented as
=>
Generally the condition for constructive interference is
![asin\theta = n * \lambda](https://img.qammunity.org/2021/formulas/physics/college/nfapuhz0qjo7jgiuyh6rmn8q6giirqdzg7.png)
Now for the first wavelength the angle is evaluated as
![\theta _1 = sin ^(-1) [ (n \lambda_1 )/(a) ]](https://img.qammunity.org/2021/formulas/physics/college/tgdx4ttf3n87y0edcbwa5rg2f439uzh2h6.png)
=>
![\theta _1 = sin ^(-1) [ (4* 434 *10^(-9) )/( 0.000147 ) ]](https://img.qammunity.org/2021/formulas/physics/college/lkykr1bsbs512dmjrq1ip4xsp8257he9ik.png)
=>
Now for the second wavelength the angle is evaluated as
![\theta _2 = sin ^(-1) [ (n \lambda_2 )/(a) ]](https://img.qammunity.org/2021/formulas/physics/college/yt39blxngwr10c82tn66vo7pzt4vqubttj.png)
=>
![\theta _2 = sin ^(-1) [ (4* 410 *10^(-9) )/( 0.000147 ) ]](https://img.qammunity.org/2021/formulas/physics/college/q0itgmext66fty6fvmcok6ofezh2cnkxoc.png)
=>
Gnerally if grating is
![N = 12800 \ slits per cm = 1280000 \ slits / m](https://img.qammunity.org/2021/formulas/physics/college/y2ri9lz84645m5zpmovbkp4tnrxi96g8bv.png)
Generally the width of the slit is mathematically represented as
=>
Generally the condition for constructive interference is
![asin\theta = n * \lambda](https://img.qammunity.org/2021/formulas/physics/college/nfapuhz0qjo7jgiuyh6rmn8q6giirqdzg7.png)
Now for the first wavelength the angle is evaluated as
![\theta _1 = sin ^(-1) [ (n \lambda_1 )/(a) ]](https://img.qammunity.org/2021/formulas/physics/college/tgdx4ttf3n87y0edcbwa5rg2f439uzh2h6.png)
![\theta _1 = sin ^(-1) [ (4* 434 *10^(-9) )/( 7.813*10^(-7) ) ]](https://img.qammunity.org/2021/formulas/physics/college/e9ihw1o7wt91u1vg5ftd2yg9mgfat6eogk.png)
=>
![\theta _1 = sin ^(-1) [ 2.22]](https://img.qammunity.org/2021/formulas/physics/college/z6b36x2ewynngk2132pl9wnoi3vy3h9nyr.png)
Generally given that the domain arcsine function is between -1 and 1 then the arcsine of 2.22 will not be valid
=>
Now for the second wavelength the angle is evaluated as
![\theta _2 = sin ^(-1) [ (n \lambda_2 )/(a) ]](https://img.qammunity.org/2021/formulas/physics/college/yt39blxngwr10c82tn66vo7pzt4vqubttj.png)
=>
![\theta _2 = sin ^(-1) [ (4* 410 *10^(-9) )/( 7.813*10^(-7) ) ]](https://img.qammunity.org/2021/formulas/physics/college/gqr31qe03rk6s7ajh4e9abah02gxmnlp2q.png)
=>
![\theta _2 = sin ^(-1) [2.1 ]](https://img.qammunity.org/2021/formulas/physics/college/y450dutfkf7sgnnm8j667skb05178e8ige.png)
Generally given that the domain arcsine function is between -1 and 1 then the arcsine of 2.22 will not be valid