Question

A 4.03 g sample of nitrogen gas has a volume of 921 milliliters at a pressure of 3.19 atm. The temperature of the N2 gas sample is:_____.

Answer 1

249 K

Step-by-step explanation:

Step 1: Given data

• Mass of nitrogen (m): 4.03 g

• Volume of the gas (V): 921 mL = 0.921 L

• Pressure of the gas (P): 3.19 atm

Step 2: Calculate the moles corresponding to 4.03 g of nitrogen

The molar mass of N₂ is 28.01 g/mol.

4.03 g × 1 mol/28.01 g = 0.144 mol

Step 3: Calculate the temperature of the gas sample

We will use the ideal gas equation.

P × V = n × R × T

T = P × V / n × R

T = 3.19 atm × 0.921 L / 0.144 mol × 0.0821 atm.L/mol.K

T = 249 K