Answer:
b. 28.0 g/mole
Step-by-step explanation:
Given:
d = 0.726 g/L
P = 0.634 atm
T = 25°C + 273 = 298 K
We can use the ideal gas equation of state:
PV= nRT
Since d=mass/V = nM/V, we can modify the equation to obtain the molar mass of the gas (M):
PM = dRT
⇒ M = dRT/P = (0.726 g/L x 0.082 L.atm/K.mol x 298 K)/(0.634 atm)= 27.87 g/mol ≅ 28 g/mol
Therefore, the correct option is b. 28.0 g/mole