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Value of p,q and r if (2^p)*(3^q)*(7^r)=1176

User Zollie
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1 Answer

4 votes

Answer:

p=3 , q=1 , r=2

Explanation:

1176=2*2*2*3*7*7

1176=(2^3)*(3^1)*(7^2)

given that 1176 = (2^p)*(3^q)*(7^r)

Comparing Equation 1 & 2

we get p=3 , q=1, r=2

User Nagat
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