Question

If a=15 and b=6, then 9a²-48ab+64b²=?​

Answer 1

9

Explanation:

Value of 'a' = 15

Value of 'b' = 6

Simplifying the expression given in question,

`9a^(2) -48ab+64b^(2)`

`=> (3a)^(2) - 2*3a*8b+(8b)^(2)`

`=>(3a-8b)^(2)`

Putting 'a' & 'b' in above expression ,

`(3a-8b)^(2) = (3*15-8*6)^(2) = (45-48)^(2) = (-3)^(2) =9`