74.9k views
4 votes
Give an example of a quadratic function that has two real solutions with a multiplicity of 2.

1 Answer

5 votes

Answer:

The equation is;

x^2 + 4x + 4 = 0

Explanation:

Here, we want to give a quadratic equation with a real solution that has a multiplicity of two

Generally, there are only two solutions to a quadratic equation since it is a polynomial of degree two

Since we have a multiplicity of 2, it means that the real roots are repeated

Let us have a solution of x = -2

With the multiplicity;

we have x + 2

So let us expand this

(x+2)(x+2)

= x^2 + 4x + 4

The equation is;

x^2 + 4x + 4 = 0

User Maciej Wojcik
by
5.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.