Answer:
The correct option is;
B.) The freezing point increases by 1 degree as the altitude increases by 10,000 feet
Explanation:
Given that the function that gives the freezing point temperature is T(a) = 0.0001·a + 32, we have;
Given that the coefficient of the straight line equation is positive, the freezing point varies positively (proportionately) with the increase in the altitude, that is as the altitude increases, the freezing point increases.
At 10,000 feet, a = 10,000, T(a) = T(10,000) = 0.0001×10,000 + 32 = 1 + 32 = 33
Therefore, the freezing point temperature increases by 1 degree for each rise (increase) in altitude of 10,000 feet.