Question

Find the perimeter of J(-4,2), K(1,2), L(2,-2) and M(-3,-2)

Answer 1

Perimeter = 31.12

Explanation:

The perimeter of the shape JKLM will be expressed as;

Perimeter = JK + JL + JM + KL + KM + LM

Using the formula for calculating the distance between two points;

D = √(x2-x1)²+(y2-y1)²

For JK where J(-4,2) and K(1,2)

JK = √(1+4)²+(2-2)²

JK = √5²

JK =√25

JK = 5

For JK where J(-4,2) and L(2,-2)

JL = √(2+4)²+(-2-2)²

JL = √6²+(-4)²

JL =√36+16

JL = √52

For JM where J(-4,2) and M(-3,-2)

JM = √(-3+4)²+(-2-2)²

JM = √1²+(-4)²

JM =√1+16

JM = √17

For KL where K(1,2), L(2,-2)

KL = √(2-1)²+(-2-2)²

KL = √1²+(-4)²

KL =√1+16

KL = √17

For KL where K(1,2), M(-3,-2)

KM = √(-3-1)²+(-2-2)²

KM = √4²+(-4)²

KM = √16+16

KM = √32

KM = 4√2

For KL where L(2,-2) and M(-3,-2)

LM = √(-3-2)²+(-2+2)²

LM = √(-5)²+(0)²

LM = √25

LM = 5

Perimeter = 5 + 4√2 + √17 + √17 + 5 + √52

Perimeter = 10 + 4√2 + 2√17 + √52

Perimeter = 10+5.66+8.25+7.21

Perimeter = 31.12