Question

N₂(g) + 3H₂(g) → 2NH3(g)

224 L of nitrogen reacts with
excess hydrogen at 2773 K and
95.0 atm. How many moles of
nitrogen react?

Answer 1

93.5 moles N₂

Step-by-step explanation:

You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.

P = 95.0 atm R = 0.0821 atm*L/mol*K

V = 224 L T = 2773 K

n = ?

PV = nRT

(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)

21280 = n(227.6633)

93.5 = n

Step-by-step explanation:

Answer 2

93.5 moles N₂

Step-by-step explanation:

To find the moles, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = number of moles

-----> R = constant (0.0821 atm*L/mol*K)

-----> T = temperature (K)

You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.

P = 95.0 atm R = 0.0821 atm*L/mol*K

V = 224 L T = 2773 K

n = ?

PV = nRT

(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)

21280 = n(227.6633)

93.5 = n