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Question 6 (1 point)

Given the following equations, what is (fog)(-6)?
f(x) = 3x² – 15
g(x) =1-
2
Оа
57
Ob
60
Oc
-61
Od
-48
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User Tiagob
by
4.9k points

1 Answer

2 votes

Answer:

See Explanation

Explanation:

The question is incomplete as g(x) is not properly written.

I'll assume the following:


f(x) = 3x^2 - 15


g(x) = 1- 2x

Required

Determine (f o g)(-6)

In functions:

(f o g)x = f(g(x))

So:


(f o g)(-6) = f(g(-6))

First, we calculate g(-6)


g(x) = 1- 2x


g(-6) = 1 - 2*-6


g(-6) = 13

Substitute 13 for g(-6) in
(f o g)(-6) = f(g(-6))


(f o g)(-6) = f(13)

Next, we calculate f(13)


f(x) = 3x^2 - 15


f(13) = 3 * 13^2 - 15


f(13) = 3 * 169 - 15


f(13) = 492

Hence:


(f o g)(-6) = 492

Use the above analysis and explanation to answer your question

User Razack
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5.0k points