Answer:
The added term needed for that expression to be a square is 9/16.
Explanation:
We're provided with two terms, and asked to add an additional term to make this a perfect square. For this to work, the term needs to be a scalar value that is the square of half the coefficient of the second term.
That coefficient is 3/2, so half of that is 3/4, and its square is 9/16.
If we tack that on the end then, we get:
![x^2 + (3x)/(2) + (9)/(16)\\=(x + (3)/(4))^2](https://img.qammunity.org/2021/formulas/mathematics/college/8fmqasqtc8cftmbbg8k2o6s2s04xwt6ugw.png)
To confirm the answer, let's expand it and see if we get the original expression:
![(x + (3)/(4))^2\\= (x + (3)/(4))(x + (3)/(4))\\= x^1 + (3x)/(4) + (3x)/(4) + (9)/(16)\\= x^2 + (6x)/(4) + (9)/(16)\\=x^2 + (3x)/(2) + (9)/(16)](https://img.qammunity.org/2021/formulas/mathematics/college/6ttj2n3i4h63kex1qkst3jyo65bm3o29dw.png)
So 9/16ths is the scalar that needs to be added on the end.