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An engineer designed a new bridge and drew the scale drawing shown below. 6 Inches If the engineer used the scale 3 inch = 40 feet, how long is the actual bridge the engineer designed?​

An engineer designed a new bridge and drew the scale drawing shown below. 6 Inches-example-1
User Tomkot
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2 Answers

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If an engineer designed a new bridge and drew the scale drawing shown below. The actual length of the bridge that the engineer designed is 80 feet.

What is the length?

The scale given is 3 inches = 40 feet which implies that every 3 inches on the scale drawing represents 40 feet in reality.

To find the length of the actual bridge set up a proportion using the given scale:

3 inches (scale drawing) corresponds to 40 feet (actual length)

6 inches (scale drawing) corresponds to x feet (actual length of the bridge)

Using the proportion:

3 inches / 40 feet = 6 inches / x feet

Cross-multiply:

3 inches * x feet = 6 inches * 40 feet

Simplify:

3x = 240

Dividing both sides by 3:

x =240/3

x = 80

Therefore the actual length of the bridge that the engineer designed is 80 feet.

User Oleksiy Ivanov
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2 votes

Answer:

The bridge is 80 feet long

Explanation:

We will use the ratio method to solve the question

∵ The engineer used the scale 3 inch = 40 feet

∴ The scale drawing is ⇒ 3 inche : 40 feet

∵ The drawing length of the bridge is 6 inches

→ By using the ratio method

→ inch : feet

→ 3 : 40

→ 6 : x

→ By using cross multiplication

3 × x = 6 × 40

∴ 3x = 240

→ Divide both sides by 3

x = 80

∵ x represents the actual length of the bridge

The bridge is 80 feet long

User Pirate X
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