Question

A treat bag has 2 green gumballs, 2 red gumballs, and one blue gumball. If you were to reach into the treat bag, write as a fraction what the probability would be that you would randomly choose: a) a green gumball, b) a red gumball, c) a blue gumball, and d) a yellow gumball.

Answer 1

Answer:welll for a and b it would be 1/2 and for c it would be 1/3 chance

Explanation:

Answer 2

Answer:
a: 2/5
b: 2/5
c: 1/5
Reasoning:
We are tying to find the probability of pulling a x colored gum-ball in fractions.

To find the divisor of all the colors you add how many gum-balls are in the bag
2+2+1= 5 gum balls in the bag.

You now add the number of that color of gun ball over the number of all the gum balls in the bag.
2 green gum balls: 2/5
2 red gum balls: 2/5
1 blue gum ball: 1/5