What is the slope of a line parallel to the line whose equation is 3x-3y=-453x−3y=−45.

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asked Oct 19, 2021 235k views

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What is the slope of a line parallel to the line whose equation is 3x-3y=-453x−3y=−45.

Mathematics
high-school

ChaTho asked

by ChaTho

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1 Answer

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Answer:

75.5x is the slope

453x+(-6y)=-45

-6y/-6y= y

-45/-6= 7.5

-453/-6= 75.5

y=7.5+ 75.5x

SergA answered Oct 23, 2021

by SergA

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