What is the slope of a line parallel to the line whose equation is 3x-3y=-453x−3y=−45.

asked Oct 19, 2021 235k views

2 votes

6.1k points

Please log in or register to add a comment.

5 votes

Answer:

75.5x is the slope

453x+(-6y)=-45

-6y/-6y= y

-45/-6= 7.5

-453/-6= 75.5

y=7.5+ 75.5x

SergA answered Oct 23, 2021

by SergA

6.0k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.5m questions

8.6m answers