Question

An object has an average acceleration of + 6.24 m/s ^ 2 for 0.300 s . At the end of this time the object's velocity is + 9.31 m/s . What was the object's initial velocity?

Answer 1

initial velocity = 7.44 m/s (3 s.f.)

Step-by-step explanation:

a = 6.24 m/s² t = 0.300 s v = 9.31 m/s u = ?

v = u + at

9.31 = u + (6.24 x 0.300)

9.31 = u + 1.872

u = 7.438

= 7.44 m/s (3 s.f.)

Hope this helps!