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1-sinA+cosA / sinA+cosA-1 = 1+cosA/sinA​

User Teej
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1 Answer

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9 votes

Solution:


(\left[\left(\sin ^(2) A+2 * \sin A * (1-\cos A)+(1-\cos A)^(2)\right]\right.)/(\left[\left(1-\cos ^(2) A\right)-(1-\cos A)^(2)\right])


(\left[\left(1-\cos ^(2) A\right)+2 * \sin A * (1-\cos A)+(1-\cos A)^(2)\right])/(\left[(1-\cos A)(1+\cos A)-(1-\cos A)^(2)\right])


((1-\cos A)[1+\cos A+2 \sin A+1-\cos A])/([1-\cos A][1+\cos A-1+\cos A])


([2+2 \sin A])/([2 * \cos A])


(2(1+\sin A))/(2 * \cos A)


(1+\cos A)/(\sin A)

Hence Proved.

User Bryan Weaver
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