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By how much will the water temperature increases if 1046 J of heat energy are added. The specific heat of water is 4.184 J/g • °C.

250°C
25°C
12.5°C
0.125°C​

User Muttonlamb
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1 Answer

2 votes

Answer:

Option A

250 degrees Celcius

Step-by-step explanation:

If 1046J of heat energy is added to water, the water will experience a rise in temperature, at a rate that is directly proportional to its specific heat capacity.

Mathematically, this can be seen as
Q=C\Delta T

Where C = specific heat of water = 4.184 J/g • °C.

Q = heat energy = 1046 J


\Delta T =1046/4.148=250 degrees Celcius

Therefore, the increase in temperature that will be experienced, is for 250 degrees Celcius

User Jeff Lambert
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