Question

A gas sample has volume 3.00 dm3 at 101

kPa. What will be the volume if the
pressure is reduced to 14.2 kPa?

Answer 1

21.3dm³

Step-by-step explanation:

Given parameters:

Initial volume of gas = 3dm³

Initial pressure = 101kPa

Final pressure = 14.2kPa

Unknown

Final volume = ?

Solution:

To solve this problem, we use the Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

Mathematically;

P₁ V₁ = P₂ V₂

P and V are pressure and Volume

1 and 2 are the initial and final states

Now insert the parameters and solve;

101 x 3 = 14.2 x V₂

V₂ = 21.3dm³