Question

How many grams of CO are needed to react with an excess of Fe 2 O 3 to produce 209.7 g Fe?

Answer 1

Mass = 157.5 g

Step-by-step explanation:

Given data:

Mass of CO needed = ?

Mass of Fe formed = 209.7 g

Solution:

Chemical equation:

3CO + F₂O₃ → 2Fe + 3CO₂

Number of moles of Fe:

Number of moles = mass/ molar mass

Number of moles = 209.7 g/ 55.85 g/mol

Number of moles = 3.75 mol

Now we will compare the moles of iron and carbon monoxide.

Fe : CO

2 : 3

3.75 ; 3/2×3.75 = 5.625 mol

Mass of CO:

Mass = number of moles × molar mass

Mass = 5.625 mol × 28 g/mol

Mass = 157.5 g