Given that log 2= 0.30103 and log 3= 0.47712. Evaluate log 12

asked Jul 20, 2023 105k views

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3 votes

Answer:

log12=log(2.2.3)

=log2+log2+log3

=0.30103+0.30103+0.47712

=0.60206+0.47712

=1.07918

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