Given:
Beau's grandmother started depositing $500 in a savings account each year in his birthday
Rate of simple interest = 2.5%
Time = 3 years
To find:
The interest.
Solution:
Formula for simple interest:

where, P is principal, r is rate of interest and t is time in years.
Interest for first year is


New principal =

Interest for second year is


New principal =

Interest for third year is


Total interest for 3 years is



So, interest after 3 years is $75.
Therefore, the correct options A.