Question

QUESTION 6 and
QUESTION 7

Answer 1

Explanation:

Q.6

`x = - 4`

`y = 5`

`\:`

`= {x}^(3) {y}^(2) - {x}^(2) y + 2xy`

`= {( - 4)}^(3) . {5}^(2) - {( - 4)}^(2) .5 + 2.( - 4).5`

`= ( - 64).25 - (16).5 + ( - 40)`

`= - 1.600 - 80 - 40`

`= - 1.720`

`\:`

`\:`

Q.7

`= {x}^(2) . {y}^(3) - {x}^(2) .y + 2xy`

`= {( - 4)}^(2) . {5}^(3) - {( - 4)}^(2) .5 + 2.( - 4).5`

`= 16.125 - (16).5 + ( - 80)`

`= 2.000 - 80 - 80`

`= 1.840`