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Sum of 1/2*3 +1/3*4 +1/4*5 ..1/99*100

User Sinkmanu
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1 Answer

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Answer:

11∗2+13∗4+15∗6+⋯+199∗100=?

=(1−12)+(13−14)+(15−16)+⋯+(199−1100)

=(1+13+15+17+⋯+199)−(12+14+16+⋯+1100)

=(1+13+15+17+⋯+199)−12(1+12+13+⋯+150)

=∑k=15012k−1−∑k=15012k

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User Cbare
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