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Line l passes through point (−2,37) and line p is the graph of y+3=−5(x+4) . If l is parallel to p what is the equation of l ?
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Line l passes through point (−2,37) and line p is the graph of y+3=−5(x+4) .

If l is parallel to p what is the equation of l ?

User Grady D
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1 Answer

8 votes

The slope of line p is -5, so substitute into point-slope form, we get


\boxed{y-37=-5(x+2)}

Line l passes through point (−2,37) and line p is the graph of y+3=−5(x+4) . If l-example-1
User Blahspam
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