Answer:
Explanation:
∠D ≅ ∠R
DC ≅ RK
So, If ∠C ≅ ∠K,
Then ΔDCS ≅ ΔRKO by Angle Side Angle congruent. {A S A}
OR
If SD ≅ OR , then
ΔDCS ≅ ΔRKO by Side Angle Side congruent {S A S}
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