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22 votes
22 votes
Halp me plss halp me plss

Halp me plss halp me plss-example-1
User Jay Prakash
by
2.5k points

2 Answers

21 votes
21 votes

Answer:


20

Skills needed: Pythagorean Theorem

Explanation:

1) First, we are given a right triangle.

---> We know this, as there is one right angle in the triangle (marked with the square-like shape --
\angle ABC).

An important term to know is: Hypotenuse

---> This is the side of the triangle opposite of the right angle.

In this case, that is the side we are solving for.

2) Now, we know we are solving for the hypotenuse, but trying to solve for it is difficult without the Pythagorean Theorem.

---> This theorem allows you to solve for any side of the right triangle when given 2 side-length values.

The formula is:
a^2+b^2=c^2


a = one of the legs (not opposite the right angle)


b = another of the legs (also not opposite the right angle)


c= hypotenuse (opposite of the right angle)

3) In this problem, we are given the two legs.

---> Now, if you are unfamiliar with this term, legs are the two sides in a right triangle that are not opposite of the right angle.

---> They are the two shorter sides.

----> In this problem they are:
12 and
16

Let's plug those in for
a and
b and solve! (below)

4)
a^2+b^2=c^2


a=12, b=16


(12)^2+(16)^2=c^2 --> Substituting in for the two legs.


144+256=c^2 --> Simplifying the exponents


400=c^2 --> Adding both like-terms on the left side


√(400)=√(c^2) --> Square-rooting both sides


20=c --> Simplifying the radicals (square roots)

----------------------------------------------------------------------------------------------------


c=20 is the answer!

User Dan Rubio
by
3.1k points
15 votes
15 votes

Answer:

Your answer is 20

Question is telling to find hypotenuse.

Consider Perpendicular as 16 and Base as 12

Use The Pythagoras theorem

Pythagoras theorem =hsquare=psquare+bsquare.

User Xin Meng
by
2.8k points