How many solutions does the following equation have? 7(y+3)=5y+8 A. No Solution B. Exactly One Solution C. Infinitely many solutions

Question

asked Nov 27, 2023 206k views

2 Answers

Hendrik Brummermann · Answer 1 · 2023-12-02T12:21:19+0000

Answer:

B. Exactly One Solution

Explanation:

Given:

7(y+3)=5y+8

Expand the brackets:

$\implies 7y + 21 = 5y + 8$

Subtract 21 from both sides:

$\implies 7y + 21-21 = 5y + 8-21$

$\implies 7y=5y-13$

Subtract 5y from both sides:

$\implies 7y-5y=5y-13-5y$

$\implies 2y=-13$

Divide both sides by 2:

$\implies (2y)/(2)=(-13)/(2)$

$\implies y=-(13)/(2)$

Therefore, the equation has exactly one solution.