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at constant pressure by what fraction of its volume will aquantity of gas change if the temperature changes from -173degree C to 27degree C

1 Answer

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Answer:

The volume of the gas becomes three times the initial volume.

Step-by-step explanation:

Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.

So, the initial temperature,
T_1 = -173 degree C = -173+273 = 100 K.

The final temperature,
T_2= 27 degree C = 27+273=300 K.

As the pressure is constant, so
P_1=P_2.

Let V_1 and V_2 be the initial and final volume respectively.

Assuming that the given gas is ideal gas.

So, applying the ideal gas equation

PV=nRT

where n is the number of moles of the gas and R is the universal gas constant.

For the initial state,
P_1V_1=n_1RT_1\cdots(i)

and for the final state,
P_2V_2=n_2RT_2 \cdots(ii)

Dividing the equation (i) by (ii), we have


\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}

As the mass of the gas is not changing, so
n_1=n_2, then


\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}

As the pressure is not changing, so
P_1=P_2, then


\frac {V_1}{V_2}=\frac {100}{300}


V_2=3V_1

So, the volume of the gas becomes three times the initial volume.

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