Answer:
The volume of the gas becomes three times the initial volume.
Step-by-step explanation:
Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.
So, the initial temperature,
= -173 degree C = -173+273 = 100 K.
The final temperature,
= 27 degree C = 27+273=300 K.
As the pressure is constant, so
.
Let V_1 and V_2 be the initial and final volume respectively.
Assuming that the given gas is ideal gas.
So, applying the ideal gas equation
PV=nRT
where n is the number of moles of the gas and R is the universal gas constant.
For the initial state,
![P_1V_1=n_1RT_1\cdots(i)](https://img.qammunity.org/2021/formulas/physics/high-school/muapijk8xt7kozo8z5ynvimunu3ak1vwt7.png)
and for the final state,
![P_2V_2=n_2RT_2 \cdots(ii)](https://img.qammunity.org/2021/formulas/physics/high-school/lino2w86dz8ateqwy1prj0ybinilr54ggw.png)
Dividing the equation (i) by (ii), we have
![\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}](https://img.qammunity.org/2021/formulas/physics/high-school/klhnzdvvhhb8tko3znadp4wrnvnh11bdtd.png)
As the mass of the gas is not changing, so
, then
![\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}](https://img.qammunity.org/2021/formulas/physics/high-school/a67fu1m8btqh9z0igm9q6zmhvdpuv1h81h.png)
As the pressure is not changing, so
, then
![\frac {V_1}{V_2}=\frac {100}{300}](https://img.qammunity.org/2021/formulas/physics/high-school/qlglfltf9ttpzxr9ftheolbiteburx6nvo.png)
![V_2=3V_1](https://img.qammunity.org/2021/formulas/physics/high-school/bw0ul8r0wzu9yh66pv9lo2p5jqzl8lggy1.png)
So, the volume of the gas becomes three times the initial volume.