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How many grams are in 22.3 mole of Copper (II) Hydroxide?

User Slebetman
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1 Answer

5 votes

Answer:

2180 g Cu(OH)₂

General Formulas and Concepts:

Chemistry - Atomic Structure

  • Reading a Periodic Table
  • Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

22.3 mol Cu(OH)₂

Step 2: Identify Conversions

Molar Mass of Cu - 63.55 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of Cu(OH)₂ - 63.55 + 2(16.00) + 2(1.01) = 97.57 g/mol

Step 3: Convert


22.3 \ mol \ Cu(OH)_2((97.57 \ g \ Cu(OH)_2)/(1 \ mol \ Cu(OH)_2) ) = 2175.81 g Cu(OH)₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

2175.81 g Cu(OH)₂ ≈ 2180 g Cu(OH)₂

User David Vielhuber
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