Question

Nico rolled two number cubes 250 times. use the complement to find the experimantal propability of not rolling a 3 on the blue number cube, NC2.

Answer 1

the probability is 0%

Explanation:

is there options like

A

B

C

options

Answer 2

1.
`\(P(5 \text{ on 1st cube and 2 on 2nd cube}) \approx 0.024\)`

2. A.
`\(P(1 \text{ on 2nd cube}) = 0.184\)`

B.
`\(P(\text{Not 1 on 2nd cube}) \approx 0.816\)`

3.
`\(P(\text{Double Sixes}) = 0.104\)`

The experimental probability of double sixes is lower than expected, likely due to the limited number of trials.

1. Experimental Probability of Rolling a 5 on the First Cube and a 2 on the Second Cube:

Count the number of times the event occurs and divide it by the total number of trials.

`\[ P(5 \text{ on 1st cube and 2 on 2nd cube}) = (6)/(250) \]`

`\[ P(5 \text{ on 1st cube and 2 on 2nd cube}) \approx 0.024 \]`

2. A. Experimental Probability of Rolling a 1 on the Second Cube:

`\[ P(1 \text{ on 2nd cube}) = (7 + 8 + 11 + 6 + 9 + 5)/(250) \]`

`\[ P(1 \text{ on 2nd cube}) = (46)/(250) \]`

`\[ P(1 \text{ on 2nd cube}) = 0.184 \]`

B. Experimental Probability of NOT Rolling a 1 on the Second Cube:

Since there are 6 possible outcomes on a number cube, the complement of rolling a 1 is rolling any other number.

`\[ P(\text{Not 1 on 2nd cube}) = 1 - P(1 \text{ on 2nd cube}) \]`

`\[ P(\text{Not 1 on 2nd cube}) = 1 - 0.184 \]`

`\[ P(\text{Not 1 on 2nd cube}) \approx 0.816 \]`

3. Experimental Probability of Rolling Double Sixes:

`\[ P(\text{Double Sixes}) = (26)/(250) \]`

`\[ P(\text{Double Sixes}) = 0.104 \]`

Reasoning:

This experimental probability is lower than the theoretical probability (1/36) of rolling double sixes with two fair six-sided dice. The observed frequency might be influenced by the limited number of trials (250), and in a larger sample size, the experimental probability is likely to approach the theoretical probability.