Question

A technician at a semiconductor facility is using an oscilloscope to measure the AC voltage across a resistor in a circuit. The technician measures the oscillating voltage to be a sine wave with a peak voltage of 3.25 V . However, the technician must record the RMS voltage on a report. What value should be reported?

Answer 1

RMS voltage is 2.29 V

Step-by-step explanation:

Given that,

The peak voltge of the voltage = 3.25 V

We need to find the RMS voltage reported by the technician.

We know that the relation between the peak and the RMS voltage is given by the formula as follows :

`V_(rms)=(V_o)/(\sqrt2)\\\\V_(rms)=(3.25)/(\sqrt2)\\\\V_(rms)=2.29\ V`

So, the RMS voltage is 2.29 V.