Question

A box slides down a ramp inclined at 24◦ to the horizontal with an acceleration of 1.7 m/s 2 . The acceleration of gravity is 9.8 m/s 2 . Determine the coefficient of kinetic friction between the box and the ramp.

Answer 1

0.445

Step-by-step explanation:

In friction, the coefficient of friction formula is expressed as;

`\mu = (F_f)/(R)`

Ff is the frictional force = Wsinθ

R is the reaction = Wcosθ

Substitute inti the equation;

`\mu = (Wsin \theta)/(W cos\theta) \\\mu = (sin \theta)/(cos\theta) \\\mu = tan \theta`

Given

θ = 24°

`\mu = tan 24^0\\\mu = 0.445\\`

Hence the coefficient of kinetic friction between the box and the ramp is 0.445