Answer:
0.533
Explanation:
Given that :
Class length has a Continuous uniform distribution between 60 - 90 min
Lower limit (L1) = 60
Upper limit (L2) = 90
Probability that class length is less than 76 min
P(x < 76):
(x - L1) / (L2 - L1)
(76 - 60) / (90 - 60)
16 / 30
= 0.533
P(x < 76) = 0.533