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Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light.

User Mamesaye
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Complete Question

Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute).Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light

Answer:

The diameter is
D = 0.59 \ m

Step-by-step explanation:

From the question we are told that

The best resolution is
\theta = 0.3 \ arcsecond

The wavelength is
\lambda = 700 \ nm = 700 *10^(-9 ) \ m

Generally the

1 arcminute = > 60 arcseconds

=> x arcminute => 0.3 arcsecond

So


x = (0.3)/(60 )

=>
x = 0.005 \ arcminutes

Now

60 arcminutes => 1 degree

0.005 arcminutes = > z degrees

=>
z = (0.005)/(60 )

=>
z = 8.333 *10^(-5) \ degree

Converting to radian


\theta = z = 8.333 *10^(-5) * 0.01745 = 1.454 *10^(-6) \ radian

Generally the resolution is mathematically represented as


\theta = (1.22 * \lambda )/( D)

=>
D = (1.22 * \lambda )/(\theta )

=>
D = (1.22 * 700 *10^(-9) )/( 1.454 *10^(-6) )

=>
D = 0.59 \ m

User Macksol
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