Complete Question
Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute).Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light
Answer:
The diameter is
Step-by-step explanation:
From the question we are told that
The best resolution is
![\theta = 0.3 \ arcsecond](https://img.qammunity.org/2021/formulas/physics/college/7os7vnvsegx71auq5cxc76rr7hkixdifm1.png)
The wavelength is
![\lambda = 700 \ nm = 700 *10^(-9 ) \ m](https://img.qammunity.org/2021/formulas/physics/college/f6oagdolwnzvok7054jnyjb2qr9hu1o4es.png)
Generally the
1 arcminute = > 60 arcseconds
=> x arcminute => 0.3 arcsecond
So
![x = (0.3)/(60 )](https://img.qammunity.org/2021/formulas/physics/college/ii55gb548xg59lhwjbpvwlixiczlw5k2j9.png)
=>
![x = 0.005 \ arcminutes](https://img.qammunity.org/2021/formulas/physics/college/nfr5xhhp6f7z4rzfc7zr8vy06wwpugomm0.png)
Now
60 arcminutes => 1 degree
0.005 arcminutes = > z degrees
=>
![z = (0.005)/(60 )](https://img.qammunity.org/2021/formulas/physics/college/7d42w1vhvi4dgg2f97jq44wqhsygry73xc.png)
=>
![z = 8.333 *10^(-5) \ degree](https://img.qammunity.org/2021/formulas/physics/college/tbvcxbejgaeym3taqwrhvvdsp6bmasq8t4.png)
Converting to radian
![\theta = z = 8.333 *10^(-5) * 0.01745 = 1.454 *10^(-6) \ radian](https://img.qammunity.org/2021/formulas/physics/college/6uwysy7s5pk3kgg24lx4hfsgu6jzx18du0.png)
Generally the resolution is mathematically represented as
![\theta = (1.22 * \lambda )/( D)](https://img.qammunity.org/2021/formulas/physics/college/ii0x7voi5yuwt3m989rxu4kaamgokgb3oz.png)
=>
![D = (1.22 * \lambda )/(\theta )](https://img.qammunity.org/2021/formulas/physics/college/14df1f9rmsc75yy59sjgmtk9r3xyb9kiff.png)
=>
=>