Answer:
John's remaining pencils in term of p = p/4
Hence, option 'c' is true.
Explanation:
Let 'p' be the total number of pencils
Given that John gives 2/3 of his pencils = 2/3 of p
= 2/3 × p
= 2/3 p
Pencils left:
![p-(2)/(3)p](https://img.qammunity.org/2021/formulas/mathematics/middle-school/isz0t207v35vrsmhxinxp7o5betc9atffz.png)
Factor out common term p
![p-(2)/(3)p=p\left(1-(2)/(3)\right)](https://img.qammunity.org/2021/formulas/mathematics/high-school/kv1n87yybtckro2z7oopskw2yoguvknvje.png)
![=(1)/(3)p](https://img.qammunity.org/2021/formulas/mathematics/high-school/zisjxa676mns8rt6paxylkmb88sxaye3jv.png)
![=(p)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fg80uukqw7qvbex1hend9fricyqwtkohhv.png)
Pencils John gave to Maria = 1/4 × p/3 = p/12
The remaining Pencils in terms of 'p' =
![(p)/(3)-(p)/(12)](https://img.qammunity.org/2021/formulas/mathematics/high-school/tacz56rcnhkrktcdtaxkqw9rrv2299ly7p.png)
![=(3p)/(12)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ena0vtw2mftlm5lqjq43lcy0jnxrpve8ud.png)
![=(p)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/fv4fbwv8bbau2nnqv6i57re7bwvwmjxcwj.png)
Thus, John's remaining pencils in term of p = p/4
Hence, option 'c' is true.