Question

Find the 10th term of the geometric sequence whose common ratio is 3/2 and whose first term is 8​

Answer 1

Answer: 19683/64

Explanation:

`a_(n)=8\left((3)/(2) \right)^(n-1)\\\\\implies a_(10)=8 \left((3)/(2) \right)^(10-1)=\boxed{(19683)/(64)}`