Find the 10th term of the geometric sequence whose common ratio is 3/2 and whose first term is 8

asked Sep 27, 2023 182k views

3 votes

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4 votes

Answer: 19683/64

Explanation:

$a_(n)=8\left((3)/(2) \right)^(n-1)\\\\\implies a_(10)=8 \left((3)/(2) \right)^(10-1)=\boxed{(19683)/(64)}$

Nikia answered Oct 3, 2023

by Nikia

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