Question

How many moles of CH3CH2Br are contained in 422 mL of 0.0950 M CH3CH2Br solution?

Answer 1

There are 0.04009 moles of CH3CH2Br in a 422 mL solution with a concentration of 0.0950 M. This is calculated by converting milliliters to liters and then using molarity to find the moles.

Step-by-step explanation:

The student is asking how to calculate the moles of CH3CH2Br in a 422 mL solution with a concentration of 0.0950 M. The solution involves converting milliliters to liters and then using the molarity as a conversion factor to find the number of moles.

To calculate the moles of CH3CH2Br in the given volume, we use the formula: moles = molarity × volume in liters. First, we convert the volume from milliliters to liters by dividing by 1000: 422 mL = 0.422 L. Then we multiply the volume in liters by the molarity: moles of CH3CH2Br = 0.0950 M × 0.422 L = 0.04009 moles.

Therefore, there are 0.04009 moles of CH3CH2Br in a 422 mL solution of 0.0950 M CH3CH2Br.

Answer 2

M= moles/L

422mL = 422/1000 = 0.422 L

0.0950 M = ? moles / 0.422 L
0.0950 Moles/ L X 0.422 L = 0.0401 moles