Question

What is the equation of the line that is parallel to the

given line and passes through the point (-3, 2)?

3x - 4y = -17
3x - 4y = -20
4x + 3y = -2
4x + 3y =-6

Answer 1

Explanation:

Let, the given point of the equation of the line are (3,-1) and (0,3) i.e

(x1,y1)=(3,-1) and (x2,y2) = (0,3)

Now,

The slope of the line (m1) = y2-y1 ÷ x2-x1

= 3-(-1) ÷ 0-3

= 3+1 ÷ -3

= 4/-3

since, the lines are parallel i.e.

m1 = m2

or, m2 = -4/3

Again,

The required equation of the line passing through the point (-3,2)=(x1,y2) is

y-y1 = m2(x-x1)

or, y-2 = -4/3 ( x +3)

or, 3(y-2) = -4(x+3)

or, 3y-6 = -4x - 12

or, 4x+3y = -12+6

Therefore, 4x+3y = -6 is the right answer.